(Solved):Maximize p = 2x + 3y subject to 3x + 8y less than or equal to 43; 6x + 4y less than or equal to 44; x greater than or equal to 0; y greater than or equal to 0. View Answer…

 

Question

Maximize {eq}p = 2x + 3y

{/eq} subject to

{eq}3x + 8y leq 43

{/eq}

{eq}6x + 4y leq 44

{/eq}

{eq}x geq 0, y geq 0

{/eq}.

 

EXPERT ANSWER

The graph of the inequalities is

where we see the feasible region in purple. The vertices may be found from the equations

{eq}3x + 8y = 43 \

8y = 43 – 3x \

y = frac{43}{8} – frac{3}{8} x \

\

6x + 4y = 44 \

4y =

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