(Solved):Maximize P subject to the following constraints, 1) P = y + 1/2 x x ge 0 y ge 0 2y – x le 1 y – 2x ge -2 2) P = 4y – x x le 2 y ge 0 x + y ge 1 2y – x le 1 View Answer…

 

Question

Maximize P subject to the following constraints,

1) P = y + 1/2 x

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